Showing posts with label current. Show all posts
Showing posts with label current. Show all posts

Tuesday, August 28, 2012

Ohm’s law

Ohm's law is the main basic electrical
law and defines the resistance of a
device to the flow of electrons.


There are three different notations of
Ohm’s law


Unknown Current


Unknown Voltage


Unknown Resistance


(Most people can remember a picture
easier than a mathematical formula.
By knowing any two values you can
figure out the third. Simply put your
finger over the portion of the symbol
you are trying to figure out and you
have your formula).





Thursday, August 23, 2012

Direct currents devices

Electrical Symbols

Electronic component are classed into
either being Passive devices or Active
devices. A Passive Device is one that
contributes no power gain to a circuit
or system. Examples are Resistors,
Light Bulb, Electrical Heaters. Active
Devices are components that are
capable of generating voltages or
currents. Examples are Batteries and
other Electrical Curent & Voltage
Sources.


By using schematics symbols we can
represent real-life devices.

Resistance -This is a resistance,
measured in units ohms ohms, . Most
often it will be a resistor.


This is a source of emf
(electromotive force) or voltage
source, with a voltage of , measured
in units of volts, V. The most common
source you will see will be a battery.
However, batteries are really not
resistance-free. We can model this
case by putting a 'resistor' in the
circuit which has the same resistance
as the batterys would have.


This is a current source, with a
current of , measured in units of
amperes , A. Current source is ideal
model of electrical power source. The
internal current source resistance is
infinity. We can model real life battery
by putting a 'resistor' in parallel with
curent source.

Voltage, Current & Resistance

In electronics we are dealing with
voltage, current and resistance in
circuits.
Voltage
Voltage is the electrical force, that
causes current to flow in a circuit. It is
measured in VOLTS .
Electrical Current
Current is the movement of electrical
charge - the flow of electrons other
charged particles through the
electronic circuit. The direction of a
current is opposite to electrons flow
direction. Current is measured in
AMPERES (AMPS, A ).
Resistance
Resistance causes an opposition to
the flow of electricity in a circuit. It is
used to control the amount of voltage
and/or amperage in a circuit. It is
measured in OHMS.
There is a relation between Voltage, Current & Resistance i.e VR=I

Sunday, August 19, 2012

Superposition theorem

In a network with multiple voltage
sources, the current in any branch is
the sum of the currents which would
flow in that branch due to each
voltage source acting alone with all
other voltage sources replaced by
their internal impedances.
The goal of folowing text is to check
superposition theorem.


Step 1. Construct following circuit
using Circuit Magic then run Node
Voltage Analysis. (popular circuits
analysis technique). You can
alsocalculate currents using other
techniques.


Electrical scheme
Inital variables
R2=10Ohms; R1 =10Ohms;
R3 =10Ohms;
E1 =3V; E3 =4V;
Solution
V1 ·G11=I11
G11=1/R1 +1/R2+1/R3=0,3
I11 =-E1/R1 -E3 /R3 =-0,7
0,3V 1 =-0,7
V1 =-2,3333
V2 =0
I1 =(V1 -V2 +E1)/R1 =0,0666667
I2=(V1-V2)/R2 =-0,233333
I3=(V1-V2+E3 )/R3=0,166667
These values are used to check
currents determined from
superposition theorem
Step 2. Remove a voltage source
from the third branch then run
Node Voltage Analysis.


Electrical scheme
Inital variables
R2=10Ohms; R1 =10Ohms;
R3 =10Ohms;
E1=3V;
Solution
V1 ·G11=I11
G11=1/R1 +1/R2 +1/R3=0,3
I11 =-E1 /R1 =-0,3
0,3V 1 =-0,3
V1 =-1
V2 =0
I1(1) =(V1 -V2 +E1)/R1 =0,2
I2(1) =(V1 -V2 )/R2 =-0,1
I3(1) =(V1 -V2 )/R3 =-0,1
These values are used to
determine current from
superposition theorem.
Step 3. Remove a voltage source
from the first branch then run
Node Voltage Analysis.


Electrical scheme
Inital variables
R2=10Ohms; R1 =10Ohms;
R3 =10Ohms;
E3=4V;
Solution
V1 ·G11=I11
G11=1/R1 +1/R2 +1/R3=0,3
I11 =-E3 /R3 =-0,4
0,3V1 =-0,4
V1 =-1,3333
V2 =0
I1(2) =(V1 -V2 )/R1 =-0,133333
I2(2) =(V1 -V2 )/R2 =-0,133333
I3(2) =(V1 -V2 +E3)/R3 =0,266667
Superposition theorem checking
I1 =I1(1) +I1(2) =0,2-0,133333=0,0666666
I2 =I2(1) +I2(2) =-0,1-0,133333=-0,233333
I3 =I3(1) +I3(2) ==-0,1+0,266667=0,166667